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4.9t^2+762t+20=0
a = 4.9; b = 762; c = +20;
Δ = b2-4ac
Δ = 7622-4·4.9·20
Δ = 580252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{580252}=\sqrt{4*145063}=\sqrt{4}*\sqrt{145063}=2\sqrt{145063}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(762)-2\sqrt{145063}}{2*4.9}=\frac{-762-2\sqrt{145063}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(762)+2\sqrt{145063}}{2*4.9}=\frac{-762+2\sqrt{145063}}{9.8} $
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